Energy in a current carrying coil is stored in the form of

$A$ $100 mH$ coil carries a current of $1 A$. Energy stored in the form of magnetic field is (in $J$)

The energy stored in an inductor of self-inductance $L$ henry carrying a current of $I$ ampere is:

If the current in an $LR$ circuit is reduced to half,what will be the energy stored in it?

$A$ coil of resistance $5 \Omega$ and inductance $4 H$ is connected to a $10 \ V$ battery. The energy stored in the coil is: (in $J$)

When a current $I$ flows through a coil,it stores the energy $E_1$ in it. Now the current is reduced to $I/2$,the energy stored in the coil becomes $E_2$. The change in the energy is